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第 43 卷 第 1 期              寻天雨等: 基于四水听器的充水弹性管声速测量方法                                           39


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             附录A


                                                                      T
                 在柱坐标系下,轴对称情况下管壁固体材料中的位移 u = (u r, u θ, u z) 和应力分量 σ rz、σ rr 为
                                  ∂Φ     ∂Φ                 ∂Φ     ∂Φ     e r ∂ (rΨ θ)  e z ∂ (rΨ θ)
                 u = ∇Φ + ∇ × Ψ =   e r +  e z + ∇ × (Ψ θe θ) =  e r +  e z −     +
                                  ∂r     ∂z                 ∂r     ∂z     r   ∂z     r   ∂r
                     (         )     (             )
                       ∂Φ   ∂Ψ θ      ∂Φ   Ψ θ  ∂Ψ θ
                   =      −      e r +   +    +      e z,
                       ∂r   ∂z         ∂z   r    ∂r
                            (          )
                              ∂u r  ∂u z
                σ rz = µε rz = µ  +     ,
                              ∂z    ∂r
                                              (                     )            (              )
                                                ∂u r  u r  1 ∂u θ  ∂u z   ∂u r     ∂u r  u r  ∂u z    ∂u r
                σ rr = λ (ε rr + ε θθ + ε zz) + 2µε rr = λ  +  +  +   + 2µ    = λ     +    +      + 2µ   .
                                                ∂r    r   r ∂θ   ∂z        ∂r      ∂r    r    ∂z       ∂r
             其中,ε rz、ε rr、ε θθ、ε zz 表示应变,在柱坐标系下,它们与固体中位移的关系为
                                        ∂u r  ∂u z      ∂u r      u r  1 ∂u θ      ∂u z
                                   ε rz =   +    , ε rr =  , ε θθ =  +      , ε zz =  .
                                        ∂z    ∂r         ∂r        r   r ∂θ        ∂z
             附录B

                 5 × 5 的矩阵 Q 的所有元素为

                                                                 k r
                          Q 11 = Q 21 = Q 31 = 0, Q 41 = J 0(k rb), Q 51 =  J 1(k rb),
                                                                ρω 2
                          Q 12 = − 2jk zk lrJ 1(k lra), Q 13 = Q 12| J(·)→N(·) ,
                                           (           2  )                     2
                                k tr         2   1   3k tr         k tr        k tr
                          Q 14 =  J 0(k tra) + k z −  −   J 1(k tra) −  J 2(k tra) +  J 3(k tra),
                                2a               a 2  4             2a          4
                          Q 15 = Q 14| J(·)→N(·) ,
                          Q 22 = Q 12| a→b, Q 23 = Q 22| J(·)→N(·) ,
                          Q 24 = Q 14| a→b, Q 25 = Q 24| J(·)→N(·) ,
                                  (      2    2  )         2
                          Q 32 = − λ (ω/c l) + µk lr J 0(k lra) + µk lr J 2(k lra),
                          Q 33 = Q 32| J(·)→N(·) , Q 34 = −µjk zk tr (J 0(k tra) − J 2(k tra)) , Q 35 = Q 34| J(·)→N(·) ,
                          Q 42 = Q 32| a→b, Q 43 = Q 42| J(·)→N(·) , Q 44 = Q 34| a→b, Q 45 = Q 44| J(·)→N(·) ,
                          Q 52 = − k lrJ 1(k lrb), Q 53 = Q 52| J(·)→N(·) , Q 54 = −jk zJ 1(k trb), Q 55 = Q 54| J(·)→N(·) .
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